3.413 \(\int \frac {x^3 (a+b \log (c x^n))}{(d+e x^r)^2} \, dx\)

Optimal. Leaf size=26 \[ \text {Int}\left (\frac {x^3 \left (a+b \log \left (c x^n\right )\right )}{\left (d+e x^r\right )^2},x\right ) \]

[Out]

Unintegrable(x^3*(a+b*ln(c*x^n))/(d+e*x^r)^2,x)

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Rubi [A]  time = 0.06, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )}{\left (d+e x^r\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[(x^3*(a + b*Log[c*x^n]))/(d + e*x^r)^2,x]

[Out]

Defer[Int][(x^3*(a + b*Log[c*x^n]))/(d + e*x^r)^2, x]

Rubi steps

\begin {align*} \int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )}{\left (d+e x^r\right )^2} \, dx &=\int \frac {x^3 \left (a+b \log \left (c x^n\right )\right )}{\left (d+e x^r\right )^2} \, dx\\ \end {align*}

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Mathematica [A]  time = 0.26, size = 140, normalized size = 5.38 \[ \frac {x^4 \left (-b n (r-4) \left (d+e x^r\right ) \, _3F_2\left (1,\frac {4}{r},\frac {4}{r};1+\frac {4}{r},1+\frac {4}{r};-\frac {e x^r}{d}\right )+4 \left (d+e x^r\right ) \, _2F_1\left (1,\frac {4}{r};\frac {r+4}{r};-\frac {e x^r}{d}\right ) \left (a (r-4)+b (r-4) \log \left (c x^n\right )-b n\right )+16 d \left (a+b \log \left (c x^n\right )\right )\right )}{16 d^2 r \left (d+e x^r\right )} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(x^3*(a + b*Log[c*x^n]))/(d + e*x^r)^2,x]

[Out]

(x^4*(-(b*n*(-4 + r)*(d + e*x^r)*HypergeometricPFQ[{1, 4/r, 4/r}, {1 + 4/r, 1 + 4/r}, -((e*x^r)/d)]) + 16*d*(a
+ b*Log[c*x^n]) + 4*(d + e*x^r)*Hypergeometric2F1[1, 4/r, (4 + r)/r, -((e*x^r)/d)]*(-(b*n) + a*(-4 + r) + b*(
-4 + r)*Log[c*x^n])))/(16*d^2*r*(d + e*x^r))

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fricas [A]  time = 0.45, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b x^{3} \log \left (c x^{n}\right ) + a x^{3}}{e^{2} x^{2 \, r} + 2 \, d e x^{r} + d^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))/(d+e*x^r)^2,x, algorithm="fricas")

[Out]

integral((b*x^3*log(c*x^n) + a*x^3)/(e^2*x^(2*r) + 2*d*e*x^r + d^2), x)

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giac [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \log \left (c x^{n}\right ) + a\right )} x^{3}}{{\left (e x^{r} + d\right )}^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))/(d+e*x^r)^2,x, algorithm="giac")

[Out]

integrate((b*log(c*x^n) + a)*x^3/(e*x^r + d)^2, x)

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maple [A]  time = 0.67, size = 0, normalized size = 0.00 \[ \int \frac {\left (b \ln \left (c \,x^{n}\right )+a \right ) x^{3}}{\left (e \,x^{r}+d \right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(b*ln(c*x^n)+a)/(e*x^r+d)^2,x)

[Out]

int(x^3*(b*ln(c*x^n)+a)/(e*x^r+d)^2,x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \log \left (c x^{n}\right ) + a\right )} x^{3}}{{\left (e x^{r} + d\right )}^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(a+b*log(c*x^n))/(d+e*x^r)^2,x, algorithm="maxima")

[Out]

integrate((b*log(c*x^n) + a)*x^3/(e*x^r + d)^2, x)

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mupad [A]  time = 0.00, size = -1, normalized size = -0.04 \[ \int \frac {x^3\,\left (a+b\,\ln \left (c\,x^n\right )\right )}{{\left (d+e\,x^r\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^3*(a + b*log(c*x^n)))/(d + e*x^r)^2,x)

[Out]

int((x^3*(a + b*log(c*x^n)))/(d + e*x^r)^2, x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{3} \left (a + b \log {\left (c x^{n} \right )}\right )}{\left (d + e x^{r}\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(a+b*ln(c*x**n))/(d+e*x**r)**2,x)

[Out]

Integral(x**3*(a + b*log(c*x**n))/(d + e*x**r)**2, x)

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